How do you solve #2^(x+2) - 2^(x+5)= -7#?

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Answer 1 · 2015-09-09T16:46:42

We have that #2^(x+2)-2^(x+5)=-7=>2^x(2^2-2^5)=-7=>2^x*(-28)=-7=>2^x=7/28=>2^x=1/4=>2^x=2^(-2)=>x=-2#