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How do you solve #2^x=10#?

1 Answer

Oct 11, 2016

#x = ln(10)/ln(2)#

Explanation:

Use any base logarithm on both sides. (I will use ln(x)):

#ln(2^x) = ln(10)#

Use the identity ln(a^b) = ln(a)b:

#ln(2)x = ln(10)#

Divide both sides by #ln(2)#:

#x = ln(10)/ln(2)#

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