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How do you solve #2 Log (x - 4) = 4 log 2#?

1 Answer

Konstantinos Michailidis

Feb 25, 2016

It is #x=8#

Explanation:

It is

#2 Log (x - 4) = 4 log 2=>log(x-4)^2=log2^4=> (x-4)^2=2^4=>(x-4)=+-4=>x=8 or x=0#

but hence #x>4# the acceptable solution is #x=8#

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