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How do you solve #2 Log (x - 4) = 4 log 2#?

1 Answer

Konstantinos Michailidis

Nov 25, 2015

We must have #x-4>0=>x>4# hence

#2log(x-4)=4log2=>log(x-4)^2=log2^4=>(x-4)^2=2^4=>x-4=+-4=>x=8 or x=0#

Finally #x=8#

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