How do you solve 2 ln x = 1?

May 3, 2016

$x = \sqrt{e}$

Explanation:

$2 \ln \left(x\right) = 1$
$\ln \left({x}^{2}\right) = 1$
${x}^{2} = {e}^{1}$
$x = \pm \sqrt{e}$

Since $\ln \left(x\right)$ is not defined for $x < 0$
$x = \sqrt{e}$