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How do you solve #2 ln x = 1#?

1 Answer

May 3, 2016

#x=sqrt(e)#

Explanation:

#2 ln(x) = 1#
#ln(x^2) = 1#
#x^2 = e^1#
#x = +-sqrt(e)#

Since #ln(x)# is not defined for #x<0#
#x = sqrt(e)#

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