How do you solve #2*7^(6x) -8 =16# and find any extraneous solutions?

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Answer 1 · 2016-08-20T18:52:26

#:. x=1.277/6=0.2128#

#2*7^(6x)-8=16#

#:. 2*7^(6x)=16+8=24#

#:. 7^(6x)=24/2=12#

#:. 6x=log_7 12#

By the Change of Base Rule, we have,

#6x=log_10 12/log_10 7=1.0792/0.8451=1.277#

#:. x=1.277/6=0.2128#