# How do you solve 2^(3x+5)=128?

$x = \frac{2}{3}$
Notice that $128 = {2}^{7}$ so
${2}^{3 x + 5} = {2}^{7}$
thus $3 x + 5 = 7$
$3 x = 2$
$x = \frac{2}{3}$