How do you solve $2^(2x-1) = 8^(x+7)$ ?

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Answer 1 · 2016-09-04T14:12:13

$x = - 22$

We have: $2^(2 x - 1) = 8^(x + 7)$

Let's express the right-hand side in terms of $2$ :

$=> 2^(2 x - 1) = (2^(3))^(x + 7)$

Using the laws of exponents:

$=> 2^(2 x - 1) = 2^(3 x + 21)$

$=> 2 x - 1 = 3 x + 21$

$=> x = - 22$

How do you solve 2^(2x-1) = 8^(x+7)2^(2x-1) = 8^(x+7)?