How do you solve $16x^2 - 64=0$ ?

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Answer 1 · 2015-06-15T11:58:26

$color(blue)(x = +-2$

$16x^2 - 64=0$

Taking out the common term $(16)$ :
$16(x^2 - 4)=0$
$x^2 - 4=0$
$x^2 =4$
$x = sqrt4$
$color(blue)(x = +-2$

How do you solve 16x^2 - 64=016x^2 - 64=0?