How do you solve #16=y+20#? Algebra Linear Equations One-Step Equations and Inverse Operations 1 Answer smendyka Jul 18, 2017 See a solution process below: Explanation: Subtract #color(red)(20)# from each side of the equation to solve for #y# while keeping the equation balanced: #16 - color(red)(20) = y + 20 - color(red)(20)# #-4 = y + 0# #-4 = y# #y = -4# Answer link Related questions What are One-Step Equations? How do you check solutions when solving one step equations? How do you solve one step equations involving addition and subtraction? How do inverse operations help solve equations? What are some examples of inverse operations? How do you solve for x in #x + 11 = 7#? How do you solve for x in #7x = 21#? How do you solve for x in # x - \frac{5}{6} = \frac{3}{8}#? How do you solve for f in #\frac{7f}{11} = \frac{7}{11}#? How do you solve for y in #\frac{3}{4} = - \frac{1}{2} \cdot y#? See all questions in One-Step Equations and Inverse Operations Impact of this question 1534 views around the world You can reuse this answer Creative Commons License