# How do you solve 14^(x+1) = 36?

Apr 19, 2016

Take the logarithm of each side. A logarithm rule lets us take the exponent outside of the logarithm.

#### Explanation:

${14}^{x + 1} = 36$

$\ln \left({14}^{x + 1}\right) = \ln \left(36\right)$

$\left(x + 1\right) \cdot \ln \left(14\right) = \ln \left(36\right)$

$\left(x + 1\right) = \ln \frac{36}{\ln \left(14\right)}$

$x = \ln \frac{36}{\ln \left(14\right)} - 1$

$x \setminus \approx 0.357878$

Substitute $x$ into the problem to check the answer.