How do you solve #14=d+(-10)#?

2 Answers
smendyka
Feb 5, 2017

See the entire solution process below:

Explanation:

Add #color(red)(10)# to each side of the equation to solve for #d# while keeping the equation balanced:

#14 + color(red)(10) = d + (-10) + color(red)(10)#

#24 = d + 0#

#d = 24#

Jim G.
Feb 5, 2017

#d=24#

Explanation:

#"Note that "+(-10)=-10#

#rArr14=d-10larr" is to be solved"#

Isolate d by adding 10 to both sides of the equation.

#14+10=dcancel(-10)cancel(+10)#

#rArrd=24" is the solution"#

Related questions
See all questions in One-Step Equations and Inverse Operations
Impact of this question
1793 views around the world
You can reuse this answer
Creative Commons License