How do you solve $14/(3x) = 6/(2x-5)$ ?

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Answer 1 · 2015-04-02T18:35:46

The answer is: $x=7$

First of all, $x !in {0, 5/2}$

Because those values will lead a "division by zero" error, which is a great sin in maths.

Now, we can get to work.

$3x * (14/(3x)) = 3x * (6/(2x-5))$

$14 = (18x)/(2x -5)$

$(2x-5) * 14 =(2x-5) * (18x)/(2x-5)$

$28x - 70 = 18x$
$10x = 70$
$x=7$

$x$ is not $0$ or $5/2$ so this is a valid value.

The result is: $x=7$

How do you solve 14/(3x) = 6/(2x-5)14/(3x) = 6/(2x-5)?