How do you solve #14> - 2x + 2> - 4#?

1 Answer
Jim G.
Apr 19, 2018

#x in (-6,3)#

Explanation:

#"subtract 2 from each interval"#

#14color(red)(-2)> -2xcancel(+2)cancel(color(red)(-2))> -4color(red)(-2)#

#rArr12> -2x > -6#

#"divide all 3 intervals by "-2#

#color(red)"Remembering to reverse the inequality signs"#

#rArr-6 < x < 3#

#x in (-6,3)larrcolor(blue)"in interval notation"#

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