How do you solve #12<8+x#? Algebra Linear Inequalities and Absolute Value Inequality Expressions 1 Answer KillerBunny Jun 21, 2018 #x>4# Explanation: Subtract #8# from both sides to get #12-8 < cancel(8)+x-cancel(8)# The left hand side becomes #12-8=4# and so we have #4<x# which is the same as #x>4# Answer link Related questions What are Inequalities? How does a linear inequality different from a linear equation? How do you graph an inequality on a number line? What are the different inequality notations? What is the difference between > and #>=#? What is the difference between set notation and interval notation? How do you graph #t>3# on a number line? What does #[3, oo)# mean? How do you graph #x \le 8#? How do you write #x > -17# as a set notation and interval notation? See all questions in Inequality Expressions Impact of this question 3747 views around the world You can reuse this answer Creative Commons License