How do you solve #10ln100x-3=117#?

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Answer 1 · 2016-09-01T10:54:15

#x=e^12/100#

the given equation is equivalent to:

#10ln(100x)=117+3#

#10ln(100x)=120#

#ln(100x)=120/10#

#ln(100x)=12#

#100x=e^12#

#x=e^12/100#