How do you solve $1/x+1>=0$ using a sign chart?

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Answer 1 · 2017-09-09T07:20:32

Solution is $x<=-1$ or $x>=0$ and in interval form it is ${x in(-oo,-1]uu[0,oo)}$

We can write $1/x+1>=0$ as $(1+x)/x>=0$

Hence, for inequality ti satisfy,

we should have sign of both $1+x$ and $x$ same i.e.

$1+x>=0$ and $x>=0$ i.e. $x>=-1$ and $x>=0$ i.e. $x>=0$

or $1+x<=0$ and $x<=0$ i.e. $x<=-1$ and $x<=0$ i.e. $x<=-1$

Hence solution is $x<=-1$ or $x>=0$ and in interval form it is ${x in(-oo,-1]uu[0,oo)}$

How do you solve 1/x+1>=01/x+1>=0 using a sign chart?