How do you solve 1.2^x -1= 104? Precalculus Solving Exponential and Logarithmic Equations Logarithmic Models 1 Answer Harish Chandra Rajpoot Jul 4, 2018 x=25.526 Explanation: 1.2^x-1=104 1.2^x=104+1 1.2^x=105 Taking log on both the sides \log(1.2^x)=\log(105) x\log(1.2)=\log(105) x=\frac{\log(105)}{\log(1.2)} x=25.526 Answer link Related questions What is a logarithmic model? How do I use a logarithmic model to solve applications? What is the advantage of a logarithmic model? How does the Richter scale measure magnitude? What is the range of the Richter scale? How do you solve 9^(x-4)=81? How do you solve logx+log(x+15)=2? How do you solve the equation 2 log4(x + 7)-log4(16) = 2? How do you solve 2 log x^4 = 16? How do you solve 2+log_3(2x+5)-log_3x=4? See all questions in Logarithmic Models Impact of this question 1467 views around the world You can reuse this answer Creative Commons License