How do you solve #1.2^x -1= 104#?

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Answer 1 · 2018-07-04T10:44:43

#x=25.526#

#1.2^x-1=104#

#1.2^x=104+1#

#1.2^x=105#

Taking log on both the sides

#\log(1.2^x)=\log(105)#

#x\log(1.2)=\log(105)#

#x=\frac{\log(105)}{\log(1.2)}#

#x=25.526#