How do you solve $1=1/(x^2+2x)+(x-1)/x$ and check for extraneous solutions?

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Answer 1 · 2016-12-24T07:58:05

$-1$

As x has to be non-zero, we can simplify the equation to the form

$1/(x+2)=1$ . So, $x = -1$ .

There is no other solution $in (-oo, oo)$ ..

How do you solve 1=1/(x^2+2x)+(x-1)/x1=1/(x^2+2x)+(x-1)/x and check for extraneous solutions?