How do you solve #(1.05)^n=2 #? Precalculus Properties of Logarithmic Functions Common Logs 1 Answer Tony B May 31, 2016 #:. n = (log 2)/(log 1.05) = 14.2067# Explanation: #= n log 1.05 = log 2# #:. n = (log 2)/(log 1.05) = 14.2067# Answer link Related questions What is the common logarithm of 10? How do I find the common logarithm of a number? What is a common logarithm or common log? What are common mistakes students make with common log? How do I find the common logarithm of 589,000? How do I find the number whose common logarithm is 2.6025? What is the common logarithm of 54.29? What is the value of the common logarithm log 10,000? What is #log_10 10#? How do I work in #log_10# in Excel? See all questions in Common Logs Impact of this question 17369 views around the world You can reuse this answer Creative Commons License