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How do you solve #(0.3)^(1 + x) = 1.7^(2x - 1)#?

1 Answer

A. S. Adikesavan

Apr 13, 2016

#x=(log 1.7+log 0.3) /(2 log 1.7 - log 0.3)=-0.2973#, nearly..

Explanation:

#log a^m=m log a#
Here, #(0.3)^(1+x)=(1.7)^(2x-1)#
Equating logarithms.
#(1+x) log 0.3=(2x-1) log 1.7#

Solving for x.
#x=(log 1.7+log 0.3) /(2 log 1.7 - log 0.3)#

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