How do you sketch the graph of $y=(x+6)^2-2$ and describe the transformation?

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Answer 1 · 2018-03-20T08:16:05

See explanation.

The graph of a function given in a form:

$y=a(x-p)^2+q$

can be obtained from the graph of

by translating it by a vector $vec(v)=[p;q]$

In the given example we have:

$a=1$ , $p=-6$ and $q=-2$

So we have to translate $y=x^2$ by $vec(v)=[-6,-2]$

graph{(y-x^2)(y-(x+6)^2+2)=0 [-10, 10, -5, 5]}