How do you sketch the graph of $y=-(x-4)^2+3$ and describe the transformation?

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Answer 1 · 2018-08-09T08:03:39

Graph

$y=-(x-4)^2 + 3$

If x is zero, $y=-13$

If x is 1, $y=-6$

etc.

The graph is below:

graph{ (-(x-4)^2) + 3 [-5.16, 14.84, -6.4, 3.6]}

How do you sketch the graph of y=-(x-4)^2+3y=-(x-4)^2+3 and describe the transformation?