How do you sketch the graph of $y=x^2+4$ and describe the transformation?

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Answer 1 · 2018-06-13T14:22:48

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Please see the explanation.

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A Quadratic Equation in standard form:

$ax^2+bx+c=0, a !=0$

graph{x^2+4 [-40, 40, -20, 20]}

$color(red)(y=x^2$ is the Parent Graph.

$color(blue)(y=x^2 +4$ is the graph of the given function.

If the coefficient of the x-term (a) is positive, the graph of the parabola Opens Up.

If the coefficient of the x-term (a) is negative, the graph of the parabola Opens Down.

The value of $c$ shifts the Vertex of the parabola Up or Down .

$c$ is also the y-intercept.

How do you sketch the graph of y=x^2+4y=x^2+4 and describe the transformation?