How do you sketch the graph of $y=-4(x+1)^2-5$ and describe the transformation?

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Answer 1 · 2018-02-07T07:05:02

Refer explanation section

Given -

$y=-4(x+1)^2-5$

It is a parabola equation in the intercept form

$y=a(x+h)^2+k$

Where -

$(h, k)$ is the vertex.

In the given equation -

$(-1, -5)$ is the vertex.

Choose a few points on either side of the vertex
Find the corresponding $y$ value.

Tabulate them -

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Plot all the points. Join with a smooth line

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How do you sketch the graph of y=-4(x+1)^2-5y=-4(x+1)^2-5 and describe the transformation?