How do you sketch the angle $- \frac{7 π}{4}$ $-(7pi)/4$ in standard position?

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Answer 1 · 2017-04-01T11:24:44

$(\frac{\sqrt{2}}{2}, \frac{\sqrt{2}}{2})$ $(sqrt 2 / 2, sqrt 2 / 2)$

Add $2 π$ $2pi$ .

$2 π - \frac{7}{4} π = \frac{π}{4} = 45^{o}$ $2pi - 7/4 pi = pi/4 = 45^o$

How do you sketch the angle −7π4-(7pi)/4 in standard position?