How do you sketch the angle $-750^circ$ in standard position?

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Answer 1 · 2016-12-30T06:56:36

The angle would be drawn as if it were a $330°$ angle.

Start from $0°$ , then go back $750°$ . That's two full turns in the negative direction and an additional $-30°$ :

$-360° + -360° + -30° = -750°$

How do you sketch the angle -750^circ-750^circ in standard position?