How do you sketch the angle $4$ $4$ in standard position?

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How do you sketch the angle $4$ $4$ in standard position?

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Answer 1 · 2017-08-04T14:29:14

The terminal side is in the third quadrant.

Explanation:

$π \approx 3.14$ $pi ~~ 3.14$ so the terminal side of $4$ $4$ is past the negative $x$ $x$ -axis.

$\frac{3 π}{2} = \frac{3}{2} \cdot π \approx \frac{3}{2} \cdot 3 = 4.5$ $(3pi)/2 = 3/2 * pi ~~ 3/2 * 3 = 4.5$ so the terminal side of $4$ $4$ is not in the fourth quadrant.

If you want to be a little more precise, note that the $\frac{π}{4}$ $pi/4$ angle in Quadrant 3 is $\frac{5 π}{4} \approx \frac{15}{4} = 3.75$ $(5pi)/4 ~~ 15/4 = 3.75$ , so the terminal side of $4$ $4$ is between those of $\frac{5 π}{4}$ $(5pi)/4$ and $\frac{3 π}{2}$ $(3pi)/2$

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How do you sketch the angle $4$ $4$ in standard position?

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