How do you simplify ${(x y z^{2})}^{4}$ $(xyz^2)^4$ ?

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Answer 1 · 2016-03-16T12:59:10

$= x^{4} y^{4} z^{8}$ $=x^4y^4z^8$

${(x y z^{2})}^{4}$ $(xyz^2)^4$

as per property:
${(a b c)}^{m} = a^{m} b^{m} c^{m}$ $color(blue)((abc))^m = a^mb^mc^m$

Applying the above to the expression

${(x y z^{2})}^{4} = x^{4} \cdot y^{4} \cdot z^{(2 \cdot 4)}$ $(xyz^2)^4 = x^4 * y^4 * z^((2*4))$

$= x^{4} y^{4} z^{8}$ $=x^4y^4z^8$

How do you simplify (xyz^2)^4(xyz2)4(xyz^2)^4?