How do you simplify $\frac{x^{8}}{2 y} \cdot \frac{5 y^{2}}{x^{3}}$ $x^8/(2y)*(5y^2)/x^3$ and write it using only positive exponents?

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Answer 1 · 2017-06-18T03:55:51

See below.

The property $\frac{x^{a}}{x^{b}} = x^{a - b}$ $x^a/x^b=x^(a-b)$ is helpful here.

This simplifies to:

$\frac{x^{8 - 3} ∙ 5 y^{2 - 1}}{2} = \frac{5 x^{5} y}{2}$ $(x^(8-3)•5y^(2-1))/2=(5x^(5)y)/2$

How do you simplify x^8/(2y)*(5y^2)/x^3x82y⋅5y2x3x^8/(2y)*(5y^2)/x^3 and write it using only positive exponents?