How do you simplify ${(x^{4})}^{4} {(x^{3})}^{5}$ $(x^4)^4 (x^3)^5$ ?

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Answer 1 · 2016-02-05T21:46:04

$x^{31}$ $x^31$

From the law of exponents : ${(x^{m})}^{n} = x^{m n}$ $(x^m)^n=x^(mn)$

We may write : ${(x^{4})}^{4} \cdot {(x^{3})}^{5} = x^{16} \cdot x^{15}$ $(x^4)^4*(x^3)^5=x^16*x^15$ .

From the law of exponents : $x^{m} \cdot x^{n} = x^{m + n}$ $x^m*x^n=x^(m+n)$

we may write : $x^{16} \cdot x^{15} = x^{16 + 15} = x^{31}$ $x^16*x^15=x^(16+15)=x^31$ .

How do you simplify (x^4)^4 (x^3)^5(x4)4(x3)5(x^4)^4 (x^3)^5?