How do you simplify $\frac{x^{2} + 2 x}{3 x} - (x^{2} + 5 x + 6)$ $(x^2+2x)/(3x) - (x^2+5x+6)$ ?

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How do you simplify $\frac{x^{2} + 2 x}{3 x} - (x^{2} + 5 x + 6)$ $(x^2+2x)/(3x) - (x^2+5x+6)$ ?

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Answer 1 · 2018-03-26T21:05:13

$(x²+2x)/(3x)-(x²+5x+6)=-((3x+8)(x+2))/3$

Explanation:

[0] $(cancel(x)*x+2*cancel(x))/(3*cancel(x))-(x^2+5x+6)$
[1] $(x+2)/3-(3x²+15x+18)/3$
[2] $(x+2-3x²-15x-18)/3$
[3] $-(3x²+14x+16)/3$
[4] $-(3x²+6x+8x+16)/3$
[5] $-(x(3x+8)+2(3x+8))/3$
[6] $-((3x+8)(x+2))/3$
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How do you simplify $\frac{x^{2} + 2 x}{3 x} - (x^{2} + 5 x + 6)$ $(x^2+2x)/(3x) - (x^2+5x+6)$ ?

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How do you simplify (x^2+2x)/(3x) - (x^2+5x+6)x2+2x3x−(x2+5x+6)(x^2+2x)/(3x) - (x^2+5x+6)?

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How do you simplify $\frac{x^{2} + 2 x}{3 x} - (x^{2} + 5 x + 6)$ $(x^2+2x)/(3x) - (x^2+5x+6)$ ?