How do you simplify: the square root of 6 (7 the square root of 3 + 6)?

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Answer 1 · 2015-08-03T14:20:52

$= 21 \sqrt{2} + 6 \sqrt{6}$ $=color(blue)(21sqrt2 + 6sqrt6$

Square root of 6 (7 the square root of 3 + 6).

Expressing the question in numbers:

$= \sqrt{6} \cdot (7 \sqrt{3} + 6)$ $=color(blue)(sqrt6*)(7sqrt3+6)$

$= \sqrt{6} \cdot (7 \sqrt{3}) + (\sqrt{6}) (6)$ $=color(blue)(sqrt6) *(7sqrt3) + color(blue)((sqrt6)) ( 6)$

$= 7 \sqrt{3} . \sqrt{6} + \sqrt{6} \cdot (6)$ $=7sqrt3.sqrt6 + sqrt6 * ( 6)$

$= 7 \sqrt{3 \cdot 6} + 6 \sqrt{6}$ $=7sqrt(3*6) + 6sqrt6$

$= 7 \sqrt{3 \cdot 3 \cdot 2} + 6 \sqrt{6}$ $=7sqrt(3*3*2) + 6sqrt6$

$= 7 \cdot 3 \sqrt{2} + 6 \sqrt{6}$ $=7*3sqrt2 + 6sqrt6$

$= 21 \sqrt{2} + 6 \sqrt{6}$ $=color(blue)(21sqrt2 + 6sqrt6$