How do you simplify the radical: $\sqrt{12} \sqrt{10}$ $sqrt12sqrt10$ ?

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How do you simplify the radical: $\sqrt{12} \sqrt{10}$ $sqrt12sqrt10$ ?

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Answer 1 · 2015-04-07T00:01:31

The answer is $2 \sqrt{30}$ $2sqrt(30)$ .

$\sqrt{12} \sqrt{10}$ $sqrt (12) sqrt (10)$

$\sqrt{10}$ $sqrt (10)$ cannot be further simplified, as it is the $\sqrt{2 \times 5}$ $sqrt (2xx5)$ , both of which are prime numbers.

$\sqrt{12} = \sqrt{4 \times 3} = 2 \sqrt{3}$ $sqrt (12)=sqrt (4xx3)=2sqrt3$
The square root of 4 is 2, and 3 is a prime number, so cannot be further simplified.

$\sqrt{12} \sqrt{10}$ $sqrt (12) sqrt (10)$ =

$2 \sqrt{3} \cdot \sqrt{10}$ $2sqrt(3)*sqrt(10)$ =

$2 \sqrt{30}$ $2sqrt (30)$

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How do you simplify the radical: $\sqrt{12} \sqrt{10}$ $sqrt12sqrt10$ ?

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How do you simplify the radical: sqrt12sqrt10√12√10sqrt12sqrt10?

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How do you simplify the radical: $\sqrt{12} \sqrt{10}$ $sqrt12sqrt10$ ?