How do you simplify the radical expression by rationalizing the denominator of $\frac{- 1 + \sqrt{3}}{\sqrt{3}}$ $(-1+sqrt3)/sqrt3$ ?

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How do you simplify the radical expression by rationalizing the denominator of $\frac{- 1 + \sqrt{3}}{\sqrt{3}}$ $(-1+sqrt3)/sqrt3$ ?

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Answer 1 · 2015-04-10T11:56:45

Multiply and divide by $\sqrt{3}$ $sqrt(3)$ :
$\frac{- 1 + \sqrt{3}}{\sqrt{3}} \cdot \frac{\sqrt{3}}{\sqrt{3}} = \frac{(- 1 + \sqrt{3}) \sqrt{3}}{3} =$ $(-1+sqrt(3))/sqrt(3)*sqrt(3)/sqrt(3)=((-1+sqrt(3))sqrt(3))/3=$
$= \frac{- \sqrt{3} + 3}{3}$ $=(-sqrt(3)+3)/3$

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How do you simplify the radical expression by rationalizing the denominator of $\frac{- 1 + \sqrt{3}}{\sqrt{3}}$ $(-1+sqrt3)/sqrt3$ ?

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How do you simplify the radical expression by rationalizing the denominator of −1+√3√3(-1+sqrt3)/sqrt3?

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How do you simplify the radical expression by rationalizing the denominator of $\frac{- 1 + \sqrt{3}}{\sqrt{3}}$ $(-1+sqrt3)/sqrt3$ ?