How do you simplify the radical expression #(3-sqrt2)/(3 +sqrt2)#? Algebra Radicals and Geometry Connections Multiplication and Division of Radicals 1 Answer Antoine Apr 6, 2015 Method: Rationalize the denominator #(3 - sqrt(2))/(3 + sqrt(2))# becomes #((3 - sqrt(2))(3 - sqrt(2)))/((3 + sqrt(2))(3 - sqrt(2)))# #=> (9 - 2(3sqrt(2)) + 2)/(9 - (2))# #=> (11 - 6sqrt(2))/7# Answer link Related questions How do you simplify #\frac{2}{\sqrt{3}}#? How do you multiply and divide radicals? How do you rationalize the denominator? What is Multiplication and Division of Radicals? How do you simplify #7/(""^3sqrt(5)#? How do you multiply #(sqrt(a) +sqrt(b))(sqrt(a)-sqrt(b))#? How do you rationalize the denominator for #\frac{2x}{\sqrt{5}x}#? Do you always have to rationalize the denominator? How do you simplify #sqrt(5)sqrt(15)#? How do you simplify #(7sqrt(13) + 2sqrt(6))(2sqrt(3)+3sqrt(6))#? See all questions in Multiplication and Division of Radicals Impact of this question 1294 views around the world You can reuse this answer Creative Commons License