How do you simplify the expression #(tanx+cotx)/cotx#?

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Answer 1 · 2016-09-22T13:32:44

#=(sinx/cosx + cosx/sinx)/(cosx/sinx)#

#= (sin^2x/(cosxsinx) + cos^2x/(cosxsinx))/(cosx/sinx)#

#=((sin^2x + cos^2x)/(cosxsinx))/(cosx/sinx)#

#=(1/(cosxsinx))/(cosx/sinx)#

#=1/(cosxsinx) xx sinx/cosx#

#=1/cos^2x#

#=sec^2x#

Hopefully this helps!