How do you simplify the expression #sin(arctan(2))#?

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Answer 1 · 2016-11-19T16:39:06

#sin(arctan(2))# does not exist.

#sin(arctan(2))=theta#,

then #sintheta=tan2#, where angle #2# is in radians.

As #2# is in radians and it is less than #(3pi)/4=2.356#

Hence #tan2<tan((3pi)/4)# i.e. #tan2<-1#

Therefore #sintheta<-1#,

but this is not possible.

Hence, #sin(arctan(2))# does not exist.