How do you simplify the expression $(sin^2theta+cos^2theta)/cos^2theta$ ?

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Answer 1 · 2018-02-22T03:43:18

$=> (1/cos^2 theta) = sec^2theta = (1 + tan^2 theta)$

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Kindly remember the following identities while solving this problem.

$sin^2theta + cos^2 theta = 1, 1 + tan ^2 theta = sec ^2 theta, sec theta = 1/ cos theta$

$cancel(sin^2 theta + cos^2 theta)^color(red)1 / cos^2 theta$

$=> (1/cos^2 theta) = sec^2theta = (1 + tan^2 theta)$

How do you simplify the expression (sin^2theta+cos^2theta)/cos^2theta(sin^2theta+cos^2theta)/cos^2theta?