How do you simplify the expression $(sec^2theta-1)/sec^2theta$ ?

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Answer 1 · 2016-10-30T21:39:59

$=>(1/cos^2theta - 1)/(1/cos^2theta)$

$=> (1/cos^2theta - cos^2theta/cos^2theta)/(1/cos^2theta)$

$=>((1 - cos^2theta)/cos^2theta)/(1/cos^2theta)$

We use the identity $sin^2beta + cos^2beta = 1-> sin^2beta = 1 - cos^2beta$ .

$=>(sin^2theta)/cos^2theta xx cos^2theta/1$

$=>sin^2theta$

Hopefully this helps!

How do you simplify the expression (sec^2theta-1)/sec^2theta(sec^2theta-1)/sec^2theta?