How do you simplify the expression $cot^2theta-csc^2theta$ ?

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Answer 1 · 2016-09-03T07:01:14

-1

Since $cot theta=cos theta/sin theta$ and $csc theta=1/sin theta$ ,

the given expression becomes:

$cos^2 theta/sin^2 theta-1/sin^2 theta=$

$(cos^2 theta-1)/sin^2 theta$

Then, since $sin^2 theta=1-cos^2 theta$ , it becomes:

$-cancel(sin^2 theta)/cancel(sin^2 theta)=-1$

How do you simplify the expression cot^2theta-csc^2thetacot^2theta-csc^2theta?