How do you simplify the expression $cosx+tanxsinx$ ?

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Answer 1 · 2016-09-02T01:59:19

$=cosx + sinx/cosx xx sinx$

$=cosx + sin^2x/cosx$

$=(cos^2x + sin^2x)/cosx$

$=1/cosx$

$=secx$

Hopefully this helps!

Answer 2 · 2016-09-02T02:01:03

$1/cos x = sec x$

$cos x + tan x sin x = cos x + (sinx/cos x) sin x$

$=cos x + (sinx)^2/cos x$

$=((cos x)^2 +(sin x)^2)/cos x$

$= 1 / cos x = sec x$

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