How do you simplify the expression #4sqrt2-6sqrt8#? Algebra Radicals and Geometry Connections Multiplication and Division of Radicals 1 Answer Don't Memorise Apr 2, 2016 # =- 8 sqrt2# Explanation: #4sqrt2 - 6 sqrt8# We first simplify #sqrt (8) = sqrt (2*2*2) = sqrt ( 2^2 *2 )= color(green)(2 sqrt2# # =4sqrt2 - 6 * color(green)((2 sqrt2)# # = 4sqrt2 - 12 sqrt2# # =- 8 sqrt2# Answer link Related questions How do you simplify #\frac{2}{\sqrt{3}}#? How do you multiply and divide radicals? How do you rationalize the denominator? What is Multiplication and Division of Radicals? How do you simplify #7/(""^3sqrt(5)#? How do you multiply #(sqrt(a) +sqrt(b))(sqrt(a)-sqrt(b))#? How do you rationalize the denominator for #\frac{2x}{\sqrt{5}x}#? Do you always have to rationalize the denominator? How do you simplify #sqrt(5)sqrt(15)#? How do you simplify #(7sqrt(13) + 2sqrt(6))(2sqrt(3)+3sqrt(6))#? See all questions in Multiplication and Division of Radicals Impact of this question 1045 views around the world You can reuse this answer Creative Commons License