How do you simplify the expression # (10sqrt2)/sqrt8#? Algebra Radicals and Geometry Connections Multiplication and Division of Radicals 1 Answer Don't Memorise Apr 28, 2016 #= 5# Explanation: #(10 sqrt2) / sqrt8# #color(blue)(sqrt8 = sqrt (2*2*2) = 2 sqrt2# #(10 sqrt2) / color(blue)(2sqrt2)# #=(10 cancelsqrt2) / color(blue)(2cancelsqrt2)# #=(10 /2 )# #= 5# Answer link Related questions How do you simplify #\frac{2}{\sqrt{3}}#? How do you multiply and divide radicals? How do you rationalize the denominator? What is Multiplication and Division of Radicals? How do you simplify #7/(""^3sqrt(5)#? How do you multiply #(sqrt(a) +sqrt(b))(sqrt(a)-sqrt(b))#? How do you rationalize the denominator for #\frac{2x}{\sqrt{5}x}#? Do you always have to rationalize the denominator? How do you simplify #sqrt(5)sqrt(15)#? How do you simplify #(7sqrt(13) + 2sqrt(6))(2sqrt(3)+3sqrt(6))#? See all questions in Multiplication and Division of Radicals Impact of this question 868 views around the world You can reuse this answer Creative Commons License