How do you simplify $\frac{{tan}^{2} y}{sec y} \div \frac{3 {tan}^{3} y}{sec y}$ $tan^2y/secydiv(3tan^3y)/secy$ ?

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How do you simplify $\frac{{tan}^{2} y}{sec y} \div \frac{3 {tan}^{3} y}{sec y}$ $tan^2y/secydiv(3tan^3y)/secy$ ?

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Answer 1 · 2016-09-03T14:08:16

$(\frac{{tan}^{2} y}{sec y}) \times (\frac{sec y}{3 {tan}^{3} y}) = \frac{1}{3 tan y} = \frac{cot y}{3}$ $(tan^2y/secy)xx((secy)/(3tan^3y))=1/(3tany)=coty/3$

Explanation:

Remember that when dividing fractions, it's the same as multiplying by the inverse. And so this:

$(\frac{{tan}^{2} y}{sec y}) \div (\frac{3 {tan}^{3} y}{sec y})$ $(tan^2y/secy)-:((3tan^3y)/secy)$ becomes

$(\frac{{tan}^{2} y}{sec y}) \times (\frac{sec y}{3 {tan}^{3} y})$ $(tan^2y/secy)xx((secy)/(3tan^3y))$

cancel out terms to get

$(\frac{{tan}^{2} y}{sec y}) \times (\frac{sec y}{3 {tan}^{3} y}) = \frac{1}{3 tan y} = \frac{cot y}{3}$ $(tan^2y/secy)xx((secy)/(3tan^3y))=1/(3tany)=coty/3$

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How do you simplify $\frac{{tan}^{2} y}{sec y} \div \frac{3 {tan}^{3} y}{sec y}$ $tan^2y/secydiv(3tan^3y)/secy$ ?

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Explanation:

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How do you simplify $\frac{{tan}^{2} y}{sec y} \div \frac{3 {tan}^{3} y}{sec y}$ $tan^2y/secydiv(3tan^3y)/secy$ ?