How do you simplify (square root of 6/square root of 7) * (square root of 14/square root of 3)?

2 Answers
Hasna K.
Apr 2, 2018

Write the roots as their factors..

Explanation:

(sqrt6/sqrt7)*(sqrt14/sqrt3)
Because we are multiplying the two fractions, we know that we can simplify by cancelling right?
Write each of the fractions, if possible, in their factors . For example : sqrt6=sqrt2*sqrt3

You should get this : ((sqrt2*sqrt3)/sqrt7)*((sqrt7*sqrt2)/sqrt3)
Cancel out any factor that is both in the numerator and the denominator.
You should be left with root 2 times root 2, which is 2 :)

Barney V.
Apr 2, 2018

2

Explanation:

sqrt6/sqrt7*sqrt14/sqrt3

:.=sqrt84/sqrt21

:.=sqrt(2*2*3*7)/sqrt21

:.sqrt2*sqrt2=2

:.=(2sqrt(3*7))/sqrt21

:.=(2cancelsqrt21^1)/cancelsqrt21^1

:.=2

Related questions
See all questions in Multiplication and Division of Radicals
Impact of this question
4667 views around the world
You can reuse this answer
Creative Commons License