How do you simplify square root of 2 times the square root of 3? Algebra Radicals and Geometry Connections Multiplication and Division of Radicals 1 Answer MeneerNask Sep 28, 2015 One rule with squares is #sqrta*sqrtb=sqrt(a*b)# Explanation: So #sqrt2*sqrt3=sqrt(2*3)=sqrt6# Answer link Related questions How do you simplify #\frac{2}{\sqrt{3}}#? How do you multiply and divide radicals? How do you rationalize the denominator? What is Multiplication and Division of Radicals? How do you simplify #7/(""^3sqrt(5)#? How do you multiply #(sqrt(a) +sqrt(b))(sqrt(a)-sqrt(b))#? How do you rationalize the denominator for #\frac{2x}{\sqrt{5}x}#? Do you always have to rationalize the denominator? How do you simplify #sqrt(5)sqrt(15)#? How do you simplify #(7sqrt(13) + 2sqrt(6))(2sqrt(3)+3sqrt(6))#? See all questions in Multiplication and Division of Radicals Impact of this question 3724 views around the world You can reuse this answer Creative Commons License