How do you simplify: square root (3/ 5)? Algebra Radicals and Geometry Connections Multiplication and Division of Radicals 1 Answer George C. Jul 26, 2015 Using #sqrt(a/b) = sqrt(a)/sqrt(b)# for #a >=0# and #b > 0# #sqrt(3/5) = sqrt((3*5)/(5*5)) = sqrt(3*5)/sqrt(5*5) = sqrt(15)/5# Explanation: We could also do it the other way: #sqrt(3/5) = sqrt(3)/sqrt(5)# #= sqrt(3)/sqrt(5)*sqrt(5)/sqrt(5)# #=(sqrt(3)sqrt(5))/(sqrt(5)sqrt(5))# #=sqrt(15)/5# using #sqrt(a)sqrt(b) = sqrt(ab)# when #a, b >= 0# Answer link Related questions How do you simplify #\frac{2}{\sqrt{3}}#? How do you multiply and divide radicals? How do you rationalize the denominator? What is Multiplication and Division of Radicals? How do you simplify #7/(""^3sqrt(5)#? How do you multiply #(sqrt(a) +sqrt(b))(sqrt(a)-sqrt(b))#? How do you rationalize the denominator for #\frac{2x}{\sqrt{5}x}#? Do you always have to rationalize the denominator? How do you simplify #sqrt(5)sqrt(15)#? How do you simplify #(7sqrt(13) + 2sqrt(6))(2sqrt(3)+3sqrt(6))#? See all questions in Multiplication and Division of Radicals Impact of this question 6233 views around the world You can reuse this answer Creative Commons License