How do you simplify $(sqrtx+4)^2$ ?

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Answer 1 · 2017-04-17T23:10:49

See the entire solution process below:

We can use this rule to simplify this expression:

$(a + b)^2 = (a + b)(a + b) = a^2 + 2ab + b^2$

Substituting $sqrt(x)$ for $a$ and $4$ for $b$ gives:

$(sqrt(x) + 4)^2 = (sqrt(x) + 4)(sqrt(x) + 4) = (sqrt(x))^2 + (2sqrt(x))*4 + 4^2$

$= x + 8sqrt(x) + 16$

How do you simplify (sqrtx+4)^2(sqrtx+4)^2?