How do you simplify $(\sqrt{x} + 3) (\sqrt{x} - 3)$ $(sqrtx+3)(sqrtx-3)$ ?

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How do you simplify $(\sqrt{x} + 3) (\sqrt{x} - 3)$ $(sqrtx+3)(sqrtx-3)$ ?

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Answer 1 · 2017-02-03T16:58:39

x - 9

Explanation:

We know $(a + b) (a + b) = a^{2} - b^{2}$ $(a+b)(a+b) = a^2 -b^2$

So $(\sqrt{x} + 3) (\sqrt{x} - 3) = {(\sqrt{x})}^{2} - {(3)}^{2} = {[x^{\frac{1}{2}}]}^{2} - 9 = x - 9$ $(sqrt x + 3)(sqrt x - 3) = (sqrt x)^2 - (3)^2 = [x^(1/2)]^2 - 9 = x - 9$

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How do you simplify $(\sqrt{x} + 3) (\sqrt{x} - 3)$ $(sqrtx+3)(sqrtx-3)$ ?

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How do you simplify $(\sqrt{x} + 3) (\sqrt{x} - 3)$ $(sqrtx+3)(sqrtx-3)$ ?