How do you simplify #(sqrtx+3)(sqrtx-3)#? Algebra Radicals and Geometry Connections Multiplication and Division of Radicals 1 Answer Nityananda Feb 3, 2017 x - 9 Explanation: We know #(a+b)(a+b) = a^2 -b^2# So #(sqrt x + 3)(sqrt x - 3) = (sqrt x)^2 - (3)^2 = [x^(1/2)]^2 - 9 = x - 9# Answer link Related questions How do you simplify #\frac{2}{\sqrt{3}}#? How do you multiply and divide radicals? How do you rationalize the denominator? What is Multiplication and Division of Radicals? How do you simplify #7/(""^3sqrt(5)#? How do you multiply #(sqrt(a) +sqrt(b))(sqrt(a)-sqrt(b))#? How do you rationalize the denominator for #\frac{2x}{\sqrt{5}x}#? Do you always have to rationalize the denominator? How do you simplify #sqrt(5)sqrt(15)#? How do you simplify #(7sqrt(13) + 2sqrt(6))(2sqrt(3)+3sqrt(6))#? See all questions in Multiplication and Division of Radicals Impact of this question 795 views around the world You can reuse this answer Creative Commons License